Section modulus is a geometric property of a flexural member like a beam that defines the strength of a given section. It is defined as the ratio of the moment of inertia of a section (I) about the neutral axis to the distance of the outermost layer from the neutral axis.
Z = I/ymax
Here, I is the Moment
of Inertia (M.O.I) about the neutral axis and ymax is the distance
of the outermost layer from the neutral axis.
As section modulus
represents the strength of a given section, the higher the value of section
modulus, the higher its strength.
Section modulus can
be of two types: elastic section modulus (Ze) and plastic section
modulus (Zp).
In this article, we
will discuss the detailed concept of section modulus and the formula to find
the elastic and plastic section modulus of a section.
As
per the simple bending theory, a section resists the bending moment by having
bending stresses. If we consider a section as shown in figure 2, with neutral
axis NA, subjected to bending will undergo compressive stresses at the top and
tension stress at the bottom.
Fig.2. Stress Distribution Along the Cross-Section Subjected to Load
We know the bending
equation is
M/I = σ/y = E/R
Where,
In the figure below
bending stress at a distance ‘y’ is σb , while the compressive stress at extreme fibre
is σbc
at a distance of ‘yc’ and the tensile stress at extreme fibre is σbt
at a distance of ‘yt’.
From the bending
equation,
At the extreme top
fibre, the compressive stress is given by:
σbc
=
M/I . yc = M/Zc
Here, Zc is the
section modulus of the section at compression;
Similarly, the
tensile stress at the extreme bottom fibre is given by:
σbt = M/Zt;
Where Zt
is the section modulus of the section at tension.
When
the section is symmetrical, i.e. the area distributed around the neutral axis
is the same and symmetrical about the neutral axis, the stress distribution will
be symmetrical about NA. This means:
yc = yt = ymax
;
σbc = σbt = M/I . ymax
= M/Z
σbc = M/Z
Z is the section modulus of the given symmetrical section. From the derivation, it is clear that the section modulus is dependent on the disposition of the area of the section with respect to the centroidal axis.
We know that a
rectangular beam that is subjected to a gradually increasing load is subjected
to bending. As the load increases, the bending stress increases. The bending
stress can be given by the equation:
σb = M. (y/I) = M/Z;
Fig.3. Plastic Bending of Beams
This bending history of the beam can be summarized to go through three stages, namely:
Let’s discuss the
elastic stage bending and plastic stage bending in detail.
At this stage of
bending, the stress σ increases with the increase in load. At this state,
σ < σy (yield stress). The stress is directly proportional to strain (e)
as per Hooke’s law until the limit of proportionality. (Figure 3 (b-2))
At σ = σy, The first yielding of the extreme fibres of the
section develops. This results in a bending moment called Yield Moment My.
My = σy. Z
At this stage, the
section is partially yielded or plasticised. After reaching yield, extreme fibres spread inwards. This results in a state where the neutral axis no longer passes through the centroid. The middle portion of the beam at
a depth of 2yo remains elastic and is called as the elastic core.
Fig.4. Beam Cross-Section at Partially Plastic Stage
Hence, the total moment of resistance is contributed from the moment (M1) from the elastic core section and the plastic core section i.e. M2.
After derivation,
M = 1.4965 My
Hence, it is clear
that at this stage, the total moment of resistance M is greater than the yield
moment My.
Note: The detailed derivation is explained in “Design of Steel Structures, B.C. Punmia, Page No: 807”
At the plastic stage, the stress in both tensile and compressive zone is equal to the yield stress and now have to pick up higher stresses. This process continues till the plastic zone gradually and progressively advances towards the neutral axis from either side.
Here the NA shifts to a new location called as the equal area axis (Figure 3 (a))whose location is determined by the fact that the total compressive force is equal to the total tensile force over the cross-section. ( Equal area axis does not pass through the centroid at this stage).
Fig.5. Beam Cross-Section at Fully-Plastic Stage
As shown in the
figure above, the two plastic zones now finally meet, as the entire
cross-section of the beam reaches the yield stress and becomes fully plastic.
When the beam
cross-section reaches the fully plastic stage, the beam rotates substantially
at the section, i.e. it becomes incapable of resisting any further increase in
the loads and in effect behaves like a rusty hinge with a constant moment of
resistance.
The bending moment
that causes the entire cross-section to remain plastic is called the Plastic Moment called Mp, which is given by:
Mp = σby. Zp
Here, Zp is the
section modulus in a plastic stage called as the Plastic Section Modulus.
As mentioned above, Zp is used for material where plastic behaviour or irreversible behaviour is dominant. The plastic section modulus merely depends on the location of the plastic neutral axis (PNA).
PNA is defined as the
axis that splits the cross-section such that the compression force from the
area in compression equals the tension forces in tension.
If the areas above
and below PNA are A1 and A2, the total moment of
resistance at plastic stage Mp = Moment due to area A1 and Moment
due to area A2
Mp = A1σy. y1 +
A2.σy.y2
Mp = σy . (A1
y1 + A2.y2)
Zp = A1 y1 + A2.y2
When the area A1=A2=A
Zp = A/2 [y1 +y2]
Hence, Zp is the first moment of
area about the neutral axis.
If the cross-section has constant yielding stress, the area above and below PNA is equal. But if it is a composite section, it may differ.
Elastic section
modulus (Ze) is defined for cross-sections that are under load conditions up to
the yield point i.e. during the elastic stage bending. This occurs at yield
moment My. Hence
My = σy . Ze
Ze = I/ymax
Where I is the second moment of inertia of the cross-section.
While plastic section
modulus (Zp) is defined for cross-section where plastic behaviour is dominant.
It occurs at the plastic moment Mp;
Mp = σy. Zp
Zp = A/2 [y1 +y2]
Shape factor (S) is the ratio of the plastic moment to yield moment.
S = Mp/My = (σy . Ze)/ σy.Zp = Zp/Ze
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